QUESTION 6 The scale on a map is given as 1 : 320,000. If the distance between the top of the two mountains on the map is 6.8cm, what is the actual distance in kilometres between the two tops of the mountain. ? show working out to prove answer.​

The actual distance is of 21.76 kilometers.

Step-by-step explanation:

Scale problems are solved by proportions, using a rule of three.

The scale on a map is given as 1 : 320,000

This means that each unit on the map represents 320,000 units of distance.

Distance between the top of the two mountains on the map is 6.8cm

Then

1 cm - 320,000 cm

6.8 cm - x

Applying cross multiplication:

Distance in kilometers

To convert from centimeters to kilometers, we divide by 100000. So

2176000/100000 = 21.76

The actual distance is of 21.76 kilometers.

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.