Lewis directs the school marching band. He uses scale drawings of the football field to design marching formations for the band. The football field is 100 yards long and yards wide. Lewis always uses a scale of 1 inch to 10 yards for his drawings. Complete the steps below to find the length and width of the football field as it appears in one of Lewis’s scale drawings.

Part A
What is the actual area of the football field? Assume that the field is shaped like a rectangle.

The length of the football field is 100 yards. The width of the field is 53 1/3 yards.

The area of a rectangle is length × width:

area = length * width

= 100 yd. * 53 1/3 yd.

= 5,333 1/3 sq. yd.

The area of the football field is 5,333 1/3 square yards.

Write a ratio to represent the scale used in the drawing.

5,333 1/3

Step-by-step explanation:

The length of the football field is 100 yards. The width of the field is 53 1/3 yards.

The area of a rectangle is length × width:

area = length * width

= 100 yd. * 53 1/3 yd.

= 5,333 1/3 sq. yd.

The area of the football field is 5,333 1/3 square yards.

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.