For the triangles to be congruent by HL, what must be the value of x?

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We have been given two right triangles. We are asked to find the value of x, which will make both triangles similar by Hypotenuse-Leg congruence.

Hypotenuse-Leg theorem states if one leg and hypotenuse of a right triangle is congruent to the one leg and hypotenuse of other right triangle, then both triangles are congruent.

So we can set an equation as:

2x + 1= 9

Upon subtracting 1 from both sides we will get,

2x+1 -1 = 9-1

2x=8

Dividing both sides of our equation by 2 we will get,

x= 4

the answer is c!

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3

circumference divided by 3.141592654 then timesthe radius twice

step-by-step explanation:

circumference divided by 3.141592654 then timesthe radius twice