G(x)=x²+5
.
Find g(a+1)-g(a-1)​

g(a + 1) - g(a - 1) = 4a

Step-by-step explanation:

g(x) = x^2 + 5,

when x = a+1, g(a+1) = (a+1)^2 + 5.

when x = a-1, g(a-1) = (a-1)^2 +5.

g(a+1)-g(a-1) = (a+1)^2 + 5 - [(a-1)^2 + 5]

= a^2 + 2a + 1 + 5 - [a^2 - 2a + 1 + 5]

= 4a

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

d i think

step-by-step explanation: