How many milliliters of 0.755 m h2so4 solution is needed to react with 55.0 ml of 2.50 m koh solution? given: 2 koh (aq) + h2so4 (aq) → 2 h2o (l) + k2so4 (aq)?

KOH  (2.50 mol/L) (0.0550 L) = 0.1375 mol  

The KOH to H2SO4 molar ratio of 2 to 1 is the key. Only H2SO4 neutralized KOH

0.1375 mol / 2 = 0.06875 mol  H2SO4 amount  

volume required of H2SO4 ---> 0.06875 mol / 0.755 mol/L = 0.0910596 L = 91.0 mL

because natural gas is colorless, odorless, and tasteless, distributors add mercaptan (a chemical that smells like sulfur) to give natural gas a distinct unpleasant odor (it smells like rotten eggs). they locate the types of rock that are likely to contain natural gas deposits.