I don't understand this
plz answer 3,4 and 5

3. Since it asked us to write question 3 in the from y=mx + c

m is the gradient

c is the intercept on y axis or where the line enters or cuts the y axis. This can be seen from the diagram. The line cuts the y axis at "9". (Check the diagram for this).

Now to find m.

Pick points on the line

Say (1,6) and (2,3)

Gradient = m = y2 - y1/(X2 - X1)

x1 = 1

y1 =6

x2 = 2

y2 = 3

Substituting into that formula

m = 3 - 6/2 - 1

m= -3/1

m= -3.

Since we've gotten what we need

y=mx + c

Y= -3x + 9.

4. 4x + 2y = 12

Rearranging by making y subject to suit the eqn...y=mx + c

you have

m is the gradient and c is the intercept.

2y = -4x + 12

Divide through by 2

y= -2x + 6

y=mx + c

By comparing...

m==gradient = -2

c== Intercept = 6

5). Doing the same thing we did above

-6x + 3y =21

Making y subject

3y = 6x + 21

Divide through by 3

y= 2x + 7

y=mx + c

m==gradient =2

c==Intercept =7.

Hope this helps.

Have a great day!

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option

there is no points to select.

step-by-step explanation: