PLEASE HELP IM ON A TIME LIMIT :( In the similarity
transformation of AACB
to AEFD, AACB was dilated by
a scale factor of [?], reflected
across the [ ], and moved
through the translation[ ].
A. 2
B. 1/2
C. 3
D. 1/3

hey hope this helps

AB =

DE

So DE = 2 × AB

and since the new triangle formed is similar to the original one, their side ratio will be same for all sides.

scale factor = AB/DE

= 2

It's been reflected across the Y-axis

moved thru the translation of 3 units towards the right of positive x- axis

for this let's compare the location of points B and D

For both the y coordinate is same while the x coordinate of B is 0 and that of D is 3

so the triangle has been shifted by 3 units across the positive x axis

the transverse axis of a hyperbola is the line that contains the two vertices and the two focuses.

in this example (hyperbola of equation x^2/2 - y^2/4 = 1), the transverse axis is the  x-axis  . 

step-by-step explanation:

it would be 6xy and -16xy.