Quentin places 58 fish in several tanks. If he places 8 fish in each tank, how many fish are not placed in the tanks but in a small fish bowl ins

2 fishes

Step-by-step explanation:

From the question, we are informed that Quentin places 58 fish in several tanks and that he places 8 fish in each tank. This means the amount of tanks that'll be used will be:

= 58/8

= 7 2/8

Since 7 tanks will be used and each tank contains 8 fishes, the number of fishes will be: = 7 × 8 = 56

Since there are 58 fishes and 56 fishes are in the tank, there'll be a remainder of (58 - 56) = 2 fishes which will be placed in the small fish bowl.

this is the formula: v = the value of investment at the end of the time period

p = the principal amount (the initial amount invested)

r = the annual interest rate

n = the annual frequency of compounding (how many times a year interest is added)

t = the number of years the money is invested

^ means raise to the power of