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9514 1404 393

  16 miles

Step-by-step explanation:

The problem can be modeled by a right triangle with one angle of 7° and the side opposite being 10,000 ft. The distance needed is the hypotenuse of the triangle, so the relevant trig relation is ...

  Sin = Opposite/Hypotenuse

  Hypotenuse = Opposite/Sin

  air distance = (10,000 ft)/sin(7°) ≈ 82,055 ft

At 5,280 ft per mile, that is ...

  (82,055 ft)/(5,280 ft/mi) ≈ 15.54 mi

The plane's air distance to the airport is about 16 miles.

answdf

step-by-step explanation: bcuz d is right

2 x^2 -3x+p

sum of roots = 3/2

let other root be x

3+ x = 3/2

x= 3/2 - 3 = -3/2

product of roots = p/2

3× -3/2 = p/2

-9 = p

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