A chemist has three different acid solutions. The first solution contains 20%
acid, the second contains 30% acid and
the third contains 50% acid. He wants to
use all three solutions to obtain a mixture
of 80 liters containing 40% acid, using
three times as much of the 50% solution
as the 30% solution. How many liters of
each solution should be used?
A. x=16, y=16, z=48
B. x=16, y = 48, z=16
C. x=24, y=14, z=42
D. X=16, y=24, z = 40

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;