A circus acrobat is shot out of a cannon with an initial upward speed of 50 . The equation for the acrobat's pathway can be modeled by the equation h = - 16t ^ 2 + 50t + 4 . a. Find the maximum height of the acrobat.

b. How long will it take to reach the ground?

Step-by-step explanation:

h = - 16t ^ 2 + 50t + 4

maximum height  take the first derivative of h (calculus if you are taking it)

h' = -32t + 50          set this equal to zero

0 = -32t +50

t = 50/32

t = 1.5625      now plug t = 1.5625  into the height equation

h = - 16(1.5625) ^ 2 + 50(1.5623) + 4

h = 43.0625 ft

you can also find the maximum height by graphing the function and locating the peak value  (much easier)

how long to reach the ground  h = zero

0 = - 16(t) ^ 2 + 50(t) + 4

use the quadratic equation to solve this or graph the function h(t) and find the roots (much easier) and you will find that

t = -0.078 and 3.203 seconds

    obviously the negative root makes no sense unless he time travelled so

t = 3.203 seconds

see below

step-by-step explanation:

x+2> 6

subtract 2 from each side

x+2-2 > 6-2

x > 4

there is an open circle at 4 since is it is greater than and the line goes to the right

answer: 33 ( approx)

step-by-step explanation:

since, in the linear regression formula, the slope is the a in the equation y = b + ax ( by comparing it with the general equation of line y = mx + c )

where,

here given table is,

price ($), x   :           18         23       25       29       30       33

pairs sold, y :         16         13         10       8         6       2

so, ,   ,   ,

and   ,

thus, slop of the given line is,

⇒  

⇒   ≈ 33