Mathematics, 26.10.2019 23:43 usabmx34
F(x) = 500(1.05)x what was the average rate of change of the value of sophia's investment from the second year to the fourth year?
Answers: 1
![\bf slope = {{ m}}= \cfrac{rise}{run} \implies \cfrac{{{ f(x_2)}}-{{ f(x_1)}}}{{{ x_2}}-{{ x_1}}}\impliedby \begin{array}{llll} average\ rate\\ of\ change \end{array}\\\\ -------------------------------\\\\ f(x)=500(1.05)^x \qquad \begin{cases} x_1=2\\ x_2=4 \end{cases}\implies \cfrac{f(4)-f(2)}{4-2} \\\\\\ \cfrac{[500(1.05)^4]~-~[500(1.05)^2]}{4-2}\implies \cfrac{56.503125}{2}\implies 28.2515625](/tpl/images/0347/9005/166a3.png)
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F(x) = 500(1.05)x what was the average rate of change of the value of sophia's investment from the s...
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