Can someone me with
i can't seem to figure this one out!
find all solutions if 0° ≤ θ < 360°. when necessary, round your answers to the nearest tenth of a degree. (enter your answers as a comma-separated list.)
sin^(2) 2θ − 7 sin 2θ − 1 = 0

but anyway, the numerator will give the angles, and θ is just half of each



ok... that's a negative tiny angle, is in the 4th quadrant, if we stick to the range given, from 0 to 360, so we have to use the positive version of it, 360-4.025

so the angle is 355.975°

now, the 3rd quadrant has another angle whose sine is negative, so... if we move from the 180° line down by 4.025, we end up at 184.025°

and those are the only two angles, because, on the 2nd and 1st quadrants, the sine is positive, so it wouldn't have an angle there