A drawer contains 3 red paper clips 5 green paper clips and 4 blue paperclips one paper clip is taken from the drawer then replaced another paper clip is taken from the drawer what is the probability that the first paper clip is red and the second paper clip is blue?

3/12 for red

4/12 for blue

Step-by-step explanation:

3 is red

5 is green

4 is blue

3 + 5 + 4 is 12 so it is out of 12 altogether

3/12 for red

4/12 for blue

1/12

Step-by-step explanation:

To find the probability of the event occuring, we need to find the probabilites of taking a red paperclip and taking a blue paperclip and then multiply them together.

Red paperclip:

3/12 = 1/4

Blue paperclip:

4/12 = 1/3

Probability of event:

3/12 x 4/12 = 12/144 = 1/12

1/4 x 1/3 = 1/12

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

it is x=-4

step-by-step explanation: