Suppose you select 2 letters at random from the word compute without replacement. find each probability. p(1 vowel and 1 consonant)

a. 1/7
b. 2/7
c. 3/7
d. 4/7

Vowels are, a, e , i, o, u, and sometimes y. The rest of the letter in the alphabet are consonants.
In the word compute there are 3 vowels and 4 consonants.
So your answer for vowels is 3/7, and your answer for consonants is 4/7.

None of those are technically correct. 9.7 x 104 is actually 1,008.8, but if that answer was a choice, it would be that one. if you meant 9.7 times maybe a thousand or more or divided by 10 or more, than the answer choices would be correct, but other than that, they actually arent.