52 cards, pull one card without replacing the card then pull second card. how do you calculate the probability that both cards you pull are 9s?

Sample size 52 cards, Event is to pull one 9 (without replacement)

There  are 4 (9's) in a card deck

P(pulling 9) = 4/52 = 1/13 =

After having pulled one 9, there are 3 9's left & obviously 51 cards

P(pulling again a 9) = 3/51

P( pulling one 9 AND AGAIN one 9) = (1/13) x (3/51) = 1/221 = 0.0045

i believe it's a.

i'm not sure on this one, most likely correct.

good luck!