Acone has a volume of 8(3.14) cubic feet and a height of 6 feet. what is the radius of the base?

Volume of a Cone = (1/3)*(pi)*(radius)*(radius)*(height)
we are given:
pi = 3.14
height = 6
Volume = 8(3.14)

plug in
8(3.14) = (1/3)*(3.14)*(radius)^2 *(6)
8 = (1/3)*(6)*(radius)^2   [divided both sides by 3.14]
8 = (2)*(radius)^2         [simplified (1/3)*(6)]
4 = (radius)^2             [divided 2 from both sides]
radius = 2             [square rooted both sides (sqrt(4))=2]

therefore the radius = 2 ft

i = 2 / - 5

step-by-step explanation:

evaluation of ( 2 - 4 ) ( p + q ) when p = 2 and q = 5 i, by putting values of p and q,                                                                    

0 = ( 2 - 4 ) ( p + q )0 = ( 2 - 4 ) ( 2 + 5 i ),   by multiplying these0 = ( 4 + 10 i - 8 - 20 i )0 = 4 - 8 + 10 i - 20 i0 = - 4 -10 i   0 = 2 ( - 2 - 5 i )0 / 2 = - 2 - 5 i- 2 - 5 i = 0- 5 i = 2i = 2 / - 5