Aball dropped from the top of the building can be modeled by the function f(t)=-16t^2 + 36 , where t represents time in seconds after the ball was dropped. a bee's flight can be modeled by the function, g(t)=3t+4, where t represents time in seconds after the bee starts the flight. the graph represents the situation. select all that applythe bee launches into flight from the ground.
the ball is dropped from a height of 36 feet.
the bee and the ball will collide after approximately 1.3 seconds.
the bee and the ball will collide after approximately 8 seconds.
the bee and the ball will collide at approximately 8 feet above the ground.
the bee and the ball will not collide.
the ball hits the ground after 1.5 seconds.

The ball is dropped from a height of 36 feet; The bee and the ball will collide after approximately 1.3 seconds; The bee and the ball will collide at approximately 8 feet above the ground; The ball hits the ground after 1.5 seconds.

Step-by-step explanation:

From the graph, we see that the bee launches into flight from y=4 feet, not from the ground.

The ball begins its descent from 36 feet.  This option is true.

The point where the bee and the ball collide is where the graphs of the two functions intersect.  This is at roughly x = 1.3 seconds.  This option is true.

Since they intersect at x = 1.3, they do not intersect at x = 8 seconds.

The y-coordinate of the point of intersection, where the bee and the ball collide, is at approximately 8 feet.  This option is true.

Since the bee and the ball collide, the next to last option is not true.

The ball reaches the x-axis, where y=0, at about 1.5 seconds.  This option is true.

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option

what i would say the best answer is a. 40.5