Variable c is 5 more than variable a. variable c is also 3 less than variable a. which pair of equations best models the relationship between c and a?

c = a − 5
c = a + 3
a = c + 5
a = 3c − 3
a = c − 5
a = 3c + 3
c = a + 5
c = a − 3

Last pair of equations.

Step-by-step explanation:

variable c is 5 more than variable a can be represented with c = 5+a and variable c is 3 less than variable a can be represented with c = a-3. So, the pair of equations are:

c = 5+a

c = a - 3.

if gloria has "carry over" minutes, (that is, any minutes paid for but not used in a month can be applied to her payment for minutes in the next month,) her total usage for the three months is: total minutes = 320 + 243 + 489 = 1052 minutes number of 200 minute blocks = 1052/200 = 5 r52 (that is 5 with a remainder of 52) rounding up the number of 200 minute blocks gives her usage for the three months as 6 blocks. the cost for six blocks is 6 x $25 = $150 she also has 200 - 52 or 148 carry over minutes if gloria pays each month and unused minutes are lost, applying the rounding up procedure to each month gives: first month usage of 320 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 second month usage of 243 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 third month usage of 489 minutes rounds up to 3 blocks of 200 minutes for a payment of 3 x $25 = $75 total payments for the three months are $50 + $50 + $75 = $175 get the plan with carry over minutes!