Me! its due
: find all values of x such that $2x^2 +9x - 5=0$ . if you find more than one value, then list your solutions in increasing order, separated by commas.

x = -5,

Step-by-step explanation:

The given equation is 2x² + 9x - 5 = 0

We have to find the values of x.

We know that if in a quadratic equation ax²+ bx + c = 0, b²- 4ac > 0 then there will be two real roots of the equation.

In the given equation b²- 4ac = (9)²-4(2)(-5) = 81 + 40

                                                = 212 > 0

So there will be two real roots.

Now we will factorize the given equation.

2x² + 9x - 5 = 0

2x² + 10x - x - 5 = 0

2x(x + 5) - 1(x + 5) = 0

(2x - 1)(x + 5) = 0

So two roots will be 2x - 1 = 0

x =

and x + 5 = 0

x = -5

Therefore, x = -5, are the solutions.

y - y1 = m(x- x1)

y - (-5) = 2/3(x -0)

y + 5 = 2/3x

y = 2/3x - 5

answer is : muchas/tipicas

have a nice day!

~recklesschicken