△abc is reflected to form △a'b'c' .

the coordinates of point a are (4, 1) , the coordinates of point b are (6, 3) , and the coordinates of point c are (2, 4) .

which reflection results in the transformation of △abc to △a'b'c' ?

reflection across the x-axis.

reflection across the y-axis

reflection across y = x.

reflection across y=−x .

Option B.

Step-by-step explanation:

It is given that △ABC is reflected to form △A'B'C' .

It is given that the vertices of triangle ABC are A(4,1), B(6,3) and C(2,4).

From the given figure it is clear that vertices of triangle A'B'C' are A'(-4,1), B'(-6,3) and C(-2,4).

The relation between preimage and image is defined by the rule

Reflection across y-axis represented by the above rule.

It means the △ABC is reflected across the y-axis to form △A'B'C' .

Therefore, the correct option is B.

a. is correct

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it