Write a quadratic function in the given form whose graph satisfies the given condition. passes through (-4, 0), (2, 0), & (6, -20) in intercept form.
pls dont just steal points away...i rly need help with this...can you provide work to if not thats ok

Step-by-step explanation:

We want to find a quadratic that passes through the points:

In intercept form.

First, note that the first two given points are the x-intercepts of our quadratic. Intercept or factored form is given by:

Where p and q are the x-intercepts.

So, we will substitute -4 and 2 for p and q:

Simplify:

Next, the third point (6, -20) tells us that y = -20 when x = 6. So:

Solve for a:

Thus:

Hence, our equation in intercept from is:

here you hope this .

step-by-step explanation:

hypotenuse = √(15² + 8²)

=  √(225 +64)

=  √(289) = 17

sin(x) = cos(y) = 8/17

they are identical so long as you are doing the sine of one angle and the cosine of the only other angle that isn't the right angle.

dhhghghghhrhbb it 5

d

step-by-step explanation: