A quadrilateral has vertices (-1,4), (2,5), (3,2) and (0,1). What special quadrilateral is formed by connecting the midpoints of the sides? A quadrilateral has vertices (-2,1), (2,2), (5,-4) and (1,-5). What special quadrilateral is formed by connecting the midpoints of the sides?
Quadrilateral EFGH has vertices E(1,8), F ( 4,7) G(4,2) and H (0,5). Which type of quadrilateral best describes EFGH?
A quadrilateral has vertices (0,3), (5,3), (8,-1) and (3,-1). What special quadrilateral is formed?

hey there!

if she's saving for six months, let's divide the total number we need for the trip by six, dividing it into the amount that needs to be saved for each month.

500 ÷ 6 =

she needs to save at least this amount each month, so we should use this symbol: ≥

let x be the amount she saves each month.

your final answer is x ≥

hope this !

l.jnl.j/n.m,lm,

step-by-step explanation:

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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