Two charged objects are separated by some distance. the charge on the first object is greater than the charge on the second object. how does the force between the two objects compare? two charged objects are separated by some distance. the charge on the first object is greater than the charge on the second object. how does the force between the two objects compare? the first object exerts a large electrostatic force on the second object. the second object exerts a large electrostatic force on the first object. the charged objects exert electrostatic forces on each other that are equal in magnitude and opposite in direction. the charged objects exert electrostatic forces on each other that are equal in magnitude and pointing in the same direction.

So we have two objects, one of charge q₁ and the other with charge q₂, separated by some distance R. and we know that q₁ >q₂-

According to Coulomb's law, the force between the charges is So here we saw that the magnitude of force that the first charge does in the second, is the same that the magnitude of the force that the second charge does in the first, because we have the product of both charges.

So the forces that each particle exert on the other is the same, now let's analyze the directions.

if the charges have the same sign, then the force is repulsive, this means that the forces point away from each other, so in this case the forces have opposite directions.

If the charges have different sign, then the force is attractive, so the forces points towards the particles, again in this case the forces have opposite directions.

So the correct answer is: The charged objects exert electrostatic forces on each other that are equal in magnitude and opposite in direction.

ill do it for 100, also this isnt 80 its 40

the electric field is a “force field” around a charged object that illustrates the direction the electric force would push an imaginary