A local university has just received a shipment of 200 Wacom tablets from an area vendor. The probability of an Wacom tablet being defective is estimated to be 0.10. A random sample of 25 Wacom tablets is selected for testing. If three or more defective Wacom tablets are found, the entire shipment of Wacom tablets is sent back to the vendor. Find the probability that the shipment will be sent back to the vendor.

0.4629

Step-by-step explanation:

Using the binomial probability relation :

P(x =x) = nCx * p^x * (1 - p)^(n - x)

Number of trials, n = 25

Probability of having defective tablet greater than 3 p(x ≥ 3) ;

p = 0.10 ;

1 - p = 1 - 0.10 = 0.90

P(x ≥ 3) = P(x = 3) + p(x = 4) + + p(x = 25)

Using a binomial probability calculator :

P(x ≥ 3) = 0.4629

Therefore, the probability that shipment would be sent back to the vendor is 0.4629

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step-by-step explanation:

£56

step-by-step explanation:

u divide 24 by 3 and u get 8 so if u do 8 time 7 or 8+8+8+8+8+8+8 u get 56 and 56 divided by 7 is 8.