Acomputer generates a random five-digit string in the symbols a, b, c, z. (a) how many such strings are possible? (b) what is the probability that the random string contains no vowels (a, e, i, o, u)? (round your answer to four decimal places.)

 (a)  11881376

(b) 0.3437

Step-by-step explanation:

Given : A computer generates a random five-digit string in the symbols A, B, C, ..., Z.

Total number of letters in English Alphabet= 26

(a) If computer generates a random five-digit string , then the total number of such strings are possible (if repetition is allowed) :-

(b) If we do not include all the vowels  (A, E, I, O, U) = 26-5=21

If computer generates a random five-digit string , then the random string contains no vowels (A, E, I, O, U) (if repetition is allowed) :-

Now, the probability that the random string contains no vowels (A, E, I, O, U) will be :_

answer:   28.56 feet (approx)

step-by-step explanation:

since, triangle abc has measure of angle c equal to 55 degrees, measure of angle abc equal to 90 degrees, and length of bc equal to 20 feet.

we have to find out the measurement of segment ab.

therefore, tan 55° =

but bc = 20 feet.

⇒ tan 55 ° =  

⇒ ab = 20 × tan 55 °

⇒ ab = 20 × 1.42814800674

⇒ ab = 28.5629601348   ≈ 28.56 feet