Solve sec^2(x) tan^2(x)+ sec(x) over 0 to 2pi A pi/2 (less than) x (less than) 3pi/2
B 0 (less than) x (less than) pi
C 0 (less than) x (less than) pi and 3pi/2 (less than or equal to) x (less than or equal to) 2pi
D 0 (less than or equal to) x (less than) pi/2 and 3pi/2 (less than) x (less than or equal to) 2pi

the functions have the same rate of change i think. i narrowed it down to this answer and "the rate of change of tour 1 is greater" but i got it wrong using that answer so im assuming its the answer above. (this is a question i also answered from the iready site if anyone needs a reference)

given : the shape of his satellite can be modeled by   where x and y are modeled in inches.

now,the given equation   is a equation of parabola.

here, coefficient of x is positive, hence the parabola opens rightwards.

on comparing this equation with standard equation , we get

in standard equation, coordinates of focus=(0,m)

thus for given equation coordinates of focus=(0,1.5)

step-by-step explanation: