Mathematics, 01.04.2021 20:40 Thejollyhellhound20
A small rocket is launched from a height of 6 feet off of the ground at an initial upward velocity of 64 feet per
second. Its height is given by the equation h=-16t^2 +64t +6, where h is the height of the rocket in feet and t
is the time since liftoff in seconds. At what time is the rocket 54 feet in the air?
A. 1 second
B. 3 seconds
C. 1 second and 3 seconds
D. none of the above
Answers: 2
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A small rocket is launched from a height of 6 feet off of the ground at an initial upward velocity o...
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