Select all the true statements. Line A G passes through points C and E. segments are drawn to create two triangles above A G, using the line as their bottom sides, and one triangle below A G using the line for its top side. The triangles above A G are A B C and E F G. The triangle below it is C D E. A C is congruent to C E and E G. A B is congruent to D E and E F. C D is 10 units and B C is 12 units. Angle C A B is 50 degrees and angle D C E is left parenthesis 5 x minus 10 right parenthesis degrees.
A. m∠CED = m∠CAB
B. m∠CAB > m∠CED
C. BC > FG
D. FG = 10
E. EG = 12

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180

answer: sherk

step-by-step explanation:

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