A ball is initially moving with a velocity 0.5m/s. Its velocity decreases at a rate of 0.05m/s^2. How much time will it take to stop? How much distance will the ball travel before it stops

 t = 10 s , s = 2,5 m

Explanation:   (1) Speed v = v0 + at and (2) distance s = v0t + ½at².

Now  v0 = 0.5 m/s , v = 0 and a = -0.05 m/s²

Solve from equation (1)   t = -v0 / a = - 0.5 m/s / -0.05 m/s² =   10 s

Add t = 10 s to equation (2 )   s = 0.5 m/s · 10 s + 0.5· (-0.05 m/s²)· (10 s)²

= 5 m - 2,5 m = 2,5 m

we need answer choices

the results is a decrease in air temperature with an increase of altitude.

explanation: