Find the area of an equilateral triangle with a radius 6 square root of 3. leave your answer in simplest radical form

you should at least use a calculater

step-by-step explanation:

i think is g(1)=-1.

hope that i can

answer: c

substitute in the values.

for a:

f(0) = 0 + 9

f(0) = 9

a is a solution.

for b:

f(7) = 14 + 9

f(7) = 23

b is a solution.

for c:

f (3) = 6 + 9

f(3) = 15

c is not a solution. it's supposed to be 14.

for d:

f(2) = 4 + 9

f(2)= 13

d is a solution.