1. a 2-kg bowling ball sits on top of a building that is 40 meters tall.

circle one: ke / gpe / both
show your work for finding the values of each type of energy the object has:

GPE = 784 J, K.E. = 0

Explanation:

An object possess gravitational potential energy due to virtue of its position and kinetic energy due to virtue of its motion. A bowling possesses only gravitational potential energy due to its position. Its not in motion, thus its kinetic energy is zero.

Gravitational potential energy is given by:

G.P.E = m g h

where m is the mass, g is acceleration due to gravity and h is the height.

m = 2.0 kg

g = 9.8 m/s²

h = 40.0 m

G.P.E = 2.0 kg × 9.8 m/s² × 40.0 m = 784.0 J

K.E. = 0.5 m v²

∵ v = 0 ⇒ K.E. = 0

answer: 802.3 kilo joules of energy represents 191.75 kilo calorie of energy.

explanation:

energy released during combustion of one mole methane = 802.3 kilo joules

if 1 kilo joule = 0.239006   kilo calorie

then ,802.3 kilo joule will be = 802.30.239006 kilo calorie

802.3 kilo joule = 191.75 kilo calorie

hence, the energy in kilo calorie is 191.75 kilo calorie.

d

explanation:

v=uf/(u-f)

= 5.10/(5-10) convex lens has positive focal length

=50/-5

=-10 cm (formed at other side)