Drag and drop the correct value next to its equivalent expression. Numbers may be used once or not at all. 10

5

6

28

14

2

3

20

1

4

27

2

3

20

3

4

Expression Value

2

3

×

42

5

12

×

26

11

15

×

20

3

8

×

54

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)

answer is  

d.

all of the above

hope you get this right

your answer is c. y = [x] + 1