There is a parallel circuit with a 120 V battery, and 3 light bulbs on separate branches. One light bulb has a resistance of 4 ohms, one light bulb has a resistance of 8 ohms, and the last light bulb
has a resistance of 2 ohms. Find the current in the circuit.

Answer is in the photo. I couldn't attach it here, but uploaded it to a file hosting. link below! Good Luck!

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fa tha first one you gonna add y to both sides

it look like this

x-y+y=6+y

x=y+6

therefore your answer is

x =y+6

fa tha second one

you gonna flip tha equation

it gonna look like x-4y=y

then add 4 to both sides

it gonna look like tha

x-4 +4 =y +4

so therefore tha answer is x=y+4

step-by-step explanation:

english, cause i can’t you