Yo guys i need help with my geometry again: Heres problem: In the diagram below, \text{m}\angle CIH = 100^{\circ}m∠CIH=100
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and \text{m}\angle BGD = 40^{\circ}.m∠BGD=40
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. Find \text{m}\angle FHG. m∠FHG.
Step Angle Reason
1
\text{m}\angle CIH=100^{\circ}m∠CIH=100
∘
Given
2
\text{m}\angle BGD=40^{\circ}m∠BGD=40
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Given
3
\text{m}\angle HIG=80^{\circ}m∠HIG=80
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Linear pair (or triple)
\text{m}\anglem∠
==
^{\circ}
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Select a Reason
(sorry if question looks weird i copied and from website lol)