The length of a side of a bigger square is one more than twice the length of a side of a smaller square if the difference in the perimeters of the squares is 16 calculate the area of the smaller square Must have let statements and two equations

Step-by-step explanation:

The perimeter of squares is just 4s

Since the bigger square has sides of 2x+1 and the smaller has sides of x the difference of perimeters is

d=4(2x+1-x)

d=4(x+1)

d=4x+4, and d=16 so

4x+4=16

4x=12

x=3 so the smaller square has sides of 3 and an area of

A=x^2

A=3^2

A=9

x is greater than 5

step-by-step explanation:

2x+7 is greater than 17

    -7                           -7

2x is greater than 10

divide by 2 each side

x is greater than 5