In a factory there are two separate containers of stress balls. In the first container are 80 balls, and in the second are 90 balls. 40% of the balls in the first container are defective, and 20% in the second container are defective. In total, how many balls in the two containers are defective?

i think ur answer is   (3,-1)

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2