the length of a rectangle park is 5 meters more than its width. if the area of the park is 300 square meters find the width of the park?

OK So Remember that perimeter P=2L+2W where L is the length and W is the width. If the length is 80 feet longer than the width, we can write the expression L=80+W. Substituting into P=2L+2W we get P=2(80+W)+2W=160+2W+2W=160+4W. Since P=300, we can say 300=160+4W. Subtracting 160 from each side we get 140=4W. Dividing each side by 4 gives 35=W. Substituting this into L=80+W gives L=80+35=115. So the length is 115 feet.

Step-by-step explanation:

f(x) has value 150 at x= 0

and 0 at x= 3

so d(f(x))/dt = slope = -150/3 = -50