Consider this quadratic equation. x + 2x + 7 = 21
The number of positive solutions to this equation is
The approximate value of the greatest solution to the equation, rounded to the nearest hundredth, is

1 solution

2.88

Step-by-step explanation:

Consider this quadratic equation.

x ^2+ 2x + 7 = 21

Subtract 7 from both sides

x ^2+ 2x + 7 -7= 21-7

x^2+2x = 14

x^2+2x -14 = 0

Factorize

x = -2±√2²-4(-14)/2

x= -2±√4+56/2

x = -2±√60/2

x = -2±7.75/2

x = -2-7.75/2 and -2+7.75/2

x = -9.75/2 and 5.75/2

x = -4.88 and 2.88

Hence there are 1 number of positive solution

The approximate value of the greatest solution to the equation, rounded to the nearest hundredth, is 2.88

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl

part a: 1.08

part b: 27.59