EASY POINTS!! PLEASE HELP

x-int. = (19/3 ,0) and (5/3 ,0)

Step-by-step explanation:

The answer would be x = 19/3, 5/3

Step-by-step explanation:

Since we are finding the x intercepts, we must set the equation to equate 0. So:

0 = 3 |x-4| - 7

Then, we want to simplify the right side so it is just the absolute value, so lets start by adding 7 to both sides.

0 = 3 |x-4| - 7

+7              +7

7= 3 |x-4|

Now we divide both sides by 3.

7= 3 |x-4|

3        3

7/3 = |x-4|

Now, due to the properties of absolute value, we must solve this twice, since absolute value always leads to a positive value, we want to set up one equation where 7/3 is positive and one where it is negative.

7/3 = x-4        -7/3 = x-4

add 4 to both sides

7/3 = x-4        -7/3 = x-4

+4      +4          +4     +4

Then, you get your two x values

x= 6.333... or 19/3 AND x = 1.66666 or 5/3

range is infinite on both x and y axis positive and negative

step-by-step explanation: