Mathematics, 19.09.2019 22:00 zafyafimli
The curvature of the helix r(t)=(acost)i+(asint)j+(bt)k (a, b is greater than or equal to 0) is k=a/(a^2+b^2). what is the largest value k can have for a given value of b?
Answers: 2
a function of 
, keeping 
fixed:
, so the numerator determines where 
has its critical points. We have
, we get a maximum curvature of
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The curvature of the helix r(t)=(acost)i+(asint)j+(bt)k (a, b is greater than or equal to 0) is k=a/...
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