Solve the quadratic formula

X^2-5x-14=0

Step-by-step explanation:

Sum = -5

Product = -14

Factors = 2 , (-7)      because 2*(-7) = -14 and 2 + (-7) = -5

x²  - 5x - 14 = 0

x² + 2x - 7x - 14 = 0

x(x + 2) -7(x + 2) = 0

(x + 2)(x - 7) =0

x + 2 = 0           ;  x -7 =0

     x = -2  ;            x  = 7

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

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step-by-step explanation: