11) To approach a runway, a pilot must begin a 10° descent starting from a height of 0.38 miles above the ground. At

the start of his approach, how far, d, is the plane from the

runway to the nearest tenth of a mile?

the plane 2.2 miles away from the runway

Step-by-step explanation:  

Given the data in the question and as illustrated in the image below;

from the image, using trigonometric ratio;

SOH CAH TOA

sin = opposite / hypotenuse

sin10° = 0.38 / x

xsin10° = 0.38

x = 0.38 / sin10°

x = 0.38 / 0.173648

x = 2.1883 miles  ≈ 2.2 miles     { the nearest tenth of a mile }

Therefore, the plane 2.2 miles away from the runway

i would say c is the best answer, hope it's right!

good luck! =)

cutie~

b is 38 degrees.

a is 52 degrees.

this is because if b is 38 and a is 14 degrees more than b than 38+14=52 and 52+38=90 degrees. hope this .