Exactly 10 disks are in a bowl. Each is marked with a different counting number selected from 1-10. Gina and Monique each select 5 disks. Two of Gina's disks are 2 and 8. Two of Monique's disks are 7 and 9. What is the largest sum that Gina's disks can have?

31

Step-by-step explanation:

The two disks that we know Gina has are: 2 and 8.

We want to find tha largest sum that Gina's disks can have:

This means that the other 3 disks must be the largest possible ones.

We know that Monique has the disks 7 and 9.

The already taken values are: 2, 7, 8, and 9.

The largest values remaining are:

10, 6 and 5.

Then the largest sum that Gyna's disks can have is given by the scenario where Gina draws these 3 disks, and the sum will be:

2 + 8 + 10 + 6 + 5 = 31

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

hope this !

56.6

step-by-step explanation:

the ratio of the perimeters is equal to the scale.

the ratio of the areas is equal to the square of the scale.

34 / 20 = k

a / 19.6 = k²

substituting:

a / 19.6 = (34 / 20)²

a = 19.6 (34 / 20)²

a ≈ 56.6