The half-life of hellium-5 is 7.6x10^-22 seconds, and the half-life of hellium-9 is 7x10^-21 seconds. Approximately how many times greater is the half-life of hellium-9 than that of helium-5?

9.2 times greater

Step-by-step explanation:

Given that :

Half life :

Helium - 9 = 7x10^-21 seconds

Helium - 5 = 7.6x10^-22 seconds

To obtain the number of tunes helium - 9 half life is greater than helium - 5 ; we divide the half life of helium-9 by the half life of helium 5

7x10^-21 seconds / 7.6x10^-22 seconds

0.9210526 x 10^(-21 - (-22))

0.9210526 * 10^1

= 0.9210526 * 10

= 9.2105

About 9.2 times greater

-7

step-by-step explanation:

x^2 + 18x + 74 = (x + 9)^2 - 81 + 74

= (x + 9)^2 - 7.

so q = -7.