Adult tickets to a play cost $22 tickets for kids cost $15. Tickets for a group of 11 cost a total of $228. How many children and how many adults went to the play?

Number of children = 2 and number of adults = 9 attended the play

Step-by-step explanation:

Step 1

Let the  number  of children be represented as  x

and the number of adults in the group  be represented as  as y

such that the total number of the group that went to the play

= x+y=11--- equation 1

And the total cost paid for the play will be expressed as

15x+  22y= 228 equation 2

Step 2-- Solving

x+y=11--- equation 1

15x+  22y= 228 equation 2

B y elimination method, multiply equation 1 by 15 to give equation 3  and then subtract from equation 2

15x+  22y= 228 equation 2

15x+15Y= 165 equation 3

7y=63

y= 63/7= 9

y= adults = 9

therefore x = number of children will be

x+y=11

x+ 9=11

x= 11-9= 2

In the group that attended the play,  Number of children = 2 and number of adults = 9

hello from mrbilldoesmath!

answer:

x - 3

discussion:

x^2 - 9 = (x-3) (x+3)   so

(x^2-9)/ (x + 3) = x-3

you,

mrb

f(2x−x2)=−3x2+6x−1

step-by-step explanation:

set up the composite function and evaluate.

f(2x−x2)=−3x2+6x−1