According to records, the amount of precipitation in a certain city on a November day has a mean of 0.10 inches, with a standard deviation of 0.07 inches. What is the probability that the mean daily precipitation will be 0.11 inches or less for a random sample of November days (taken over many years)? Carry your intermediate computations to at least four decimal places. Round your answer to at least three decimal places.

The probability that the mean daily precipitation will be 0.11 inches or less for a random sample of November days

P(X≤ 0.11) = 0.4404

Step-by-step explanation:

Step(i):-

Given that the mean of the Population = 0.10 inches

Given that the standard deviation of the population = 0.07inches

Let 'X' be a random variable in a normal distribution

Step(ii):-

The probability that the mean daily precipitation will be 0.11 inches or less for a random sample of November days

P(X≤ 0.11) = P(Z≤0.1428)

               =  1-P(Z≥0.1428)

              =  1 - ( 0.5 +A(0.1428)

            =  0.5 - A(0.1428)

            = 0.5 -0.0596

           = 0.4404

Final -

The probability that the mean daily precipitation will be 0.11 inches or less for a random sample of November days

P(X≤ 0.11) = 0.4404

astronomers is your final answer! : )