∠A and \angle B∠B are complementary angles. If m\angle A=(2x-10)^{\circ}∠A=(2x−10) ∘ and m\angle B=(x-2)^{\circ}∠B=(x−2) ∘ , then find the measure of \angle A∠A.

118°

Step-by-step explanation:

Two angles are called complementary when their measures add to 90 degrees.

From the question,

Angle A=(2x-10)°

Angle B=(x-2)°

Both Angles are complementary.

Therefore

Step 1

(2x - 10)° + (x - 2)° = 180°

2x + x - 10 - 2 = 180°

3x - 12 = 180°

3x = 180° + 12

3x = 192°

x = 192/3

x = 64°

Step 2

We are to solve for Angle A

(2x-10)°

Angle A = 2(64 ) - 10

Angle A = 128 - 10

Angle A = 118°

The measure of Angle A = 118°

step-by-step explanation:

the length of o'p' is .

step-by-step explanation:

it is given that the quadrilateral m'n'o'p' is the image of quadrilateral mnop after dilation.

the center of dilation is origin and the scale factor is 1.5.

in dilation the image and preimge are similar figures. it means the sides of image and preimage are proportional.

the scale factor is defined as

the scale factor is 1.5.

multiply both sides by op.

note: if the value of op is given, then multiply the value of op with 1.5 to get the length of side o'p'.

therefore length of o'p' is .