The ionic salt KBr is dissolved in water, much like the experiments given in the simulation. A mass of 98.0 g of salt is added to 100. g of water. Both start at a temperature of 23.0 ∘C. ΔHsoln for KBr is 8.00 kJ/mol . Given this information, calculate the final temperature

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally