1. The perimeter of a piece of paper is 18 cm. a. List three different possible sets of dimensions for the paper, as well as the resulting areas.

a) length = 3 and width = 6

Area of the rectangle = 3 × 6 = 18 cm²

b)  length = 7 and width = 2

Area of the rectangle = 7 × 2 = 14 cm²

c)  length = 5 and width = 4

Area of the rectangle = 5× 4 = 20 cm²

Step-by-step explanation:

Step(i):-

Given perimeter of the paper = 18 cm

we know that the paper has a rectangle shape

The perimeter of the rectangle = 18 cm

 2( l + w ) = 18

a)

we choose length = 3 and width = 6

The perimeter of the rectangle = 2( 3+6) = 18 cm

Area of the rectangle = 3 × 6 = 18 cm²

b)

we choose length = 7 and width = 2

The perimeter of the rectangle = 2( 7+2) = 18 cm

Area of the rectangle = 7 × 2 = 14 cm²

c)

we choose length = 5 and width = 4

The perimeter of the rectangle = 2( 5+4) = 18 cm

Area of the rectangle = 5× 4 = 20 cm²

step-by-step explanation:

one of the most important purposes of surface treatment is to alter surface properties according to the requirement of specific applications. for example, hydrophobic coating has been utilized on windshield and eyeglasses. gold atom monolayer on substrate has become a popular surface bioconjugation strategy.  

24

step-by-step explanation:

the graph shows 30% of students walk. 80 students were questioned, so the number that said they walk is

30% × 80 = 0.30 × 80 = 24